Question

In the reaction: 2Na(s) + Cl2(g) → 2NaCl(g) If 53.2 g Na reacts with 65.8 g Cl₂, What the theoritical yield of NaCl is formed

A 80.9
B 106 g
C 25.7
D 66.5
E none of these

Answer 1

First, we need to find the limiting reactant.


Calculate the moles of Na:
53.2 g Na * (1 mol Na / 22.99 g Na


Calculate the moles of Cl2:
65.8 g Cl2 * (1 mol Cl2 / 35.45 g Cl2) = 1.86 mol Cl2


Divide the moles of each reactant by their respective stoichiometric coefficient from the balanced equation to find the limiting reactant:
Na: 2.31 mol Na / 2 = 1.16
Cl2: 1.86 mol Cl2 / 1 = 1.86


The limiting react is Na, so we will use it to determine the theoretical yield of NaCl.

Calculate the theoretical yield of NaCl using the moles of Na:
1.16 moles of Na * (1 mole NaCl / 2 moles Na) * (58.44 g NaCl / 1 mol NaCl) = 33.94 g NaCl

The theoretical yield of NaCl formed is 33.94 g.
Therefore, the correct answer is E) none of these.