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بواسطة
ا ب ج د شكل رباعي فيه ب ج =٣ ا د أثبت أن:1)ا ب ج د شبه منحرف 2(ا ج+ب د =ا د

1 إجابة واحدة

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بواسطة
Given: a quadrilateral ABCD with AB = BC = 3.
To prove:

Quadrilateral ABCD is a parallelogram.
AC + BD = AD

Proof:
1)
Since AB = BC, angle ABC = angle BCA (Isosceles triangle property).
Therefore, angle ABC = angle BCD (vertically opposite angles).
Since angle ABC = angle BCD, quadrilateral ABCD has opposite sides that are parallel (consecutive interior angles theorem).
Therefore, quadrilateral ABCD is a parallelogram.



In parallelogram ABCD, opposite sides are equal in length.
So, AC = BD and AD = BC.
Therefore, AC + BD = BD + BD = 2BD.
Also, AD = BC = 3.
Therefore, AC + BD = 2BD = 3.
مرحبًا بك إلى يزيد، حيث يمكنك طرح الأسئلة وانتظار الإجابة عليها من المستخدمين الآخرين.
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